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<title>GATE Overflow for GATE XE - Recent questions and answers in Thermodynamic Cycles</title>
<link>https://xe.gateoverflow.in/qa/thermodynamics/thermodynamic-cycles</link>
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<title>GATE XE 2026 | Question: 86</title>
<link>https://xe.gateoverflow.in/912/gate-xe-2026-question-86</link>
<description>Consider an ideal Otto-cycle with cold-air-standard assumptions to be applicable. The temperature of the working fluid at the start and the end of the compression process is $300$ $\mathrm{K}$ and $750$ $\mathrm{K}$, respectively. For the working fluid take the ratio of the specific heat capacities as $1.4$. The thermal efficiency (in $\%$) of the cycle is $\_\_\_\_$ (rounded off to two decimal places).</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/912/gate-xe-2026-question-86</guid>
<pubDate>Tue, 24 Feb 2026 15:40:20 +0000</pubDate>
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<title>GATE XE 2026 | Question: 90</title>
<link>https://xe.gateoverflow.in/908/gate-xe-2026-question-90</link>
<description>&lt;p&gt;Consider an ideal Rankine cycle with fixed conditions at the turbine inlet. If the condenser pressure is lowered, which of the following statements is/are &lt;strong&gt;CORRECT&lt;/strong&gt;?&lt;/p&gt;&lt;ol start=&quot;1&quot; style=&quot;list-style-type: upper-alpha;&quot;&gt;&lt;li&gt;Pump work input remains the same.&lt;/li&gt;&lt;li&gt;Moisture content at turbine exit decreases.&lt;/li&gt;&lt;li&gt;Heat rejected in the condenser decreases.&lt;/li&gt;&lt;li&gt;Turbine work output increases.&lt;/li&gt;&lt;/ol&gt;</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/908/gate-xe-2026-question-90</guid>
<pubDate>Tue, 24 Feb 2026 15:39:22 +0000</pubDate>
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<title>GATE XE 2025 | Question: 92</title>
<link>https://xe.gateoverflow.in/698/gate-xe-2025-question-92</link>
<description>&lt;p&gt;​​​​​If $\gamma$ refers to the ratio of specific heats, the air-standard efficiency of an Otto cycle is&lt;/p&gt;

&lt;ol start=&quot;1&quot; style=&quot;list-style-type:upper-alpha&quot;&gt;
	&lt;li&gt;$1-\frac{1}{(\text { Compression ratio })^{\gamma}}$&lt;/li&gt;
	&lt;li&gt;$1-\frac{1}{(\text { Pressure ratio) } ^{\frac{\gamma-1}{\gamma}}.}$&lt;/li&gt;
	&lt;li&gt;$1-\frac{1}{(\text { Compression ratio })^{(\gamma-1)}}$&lt;/li&gt;
	&lt;li&gt;$1-\frac{1}{(\text { Pressure ratio })^{(\gamma-1)}}$&lt;/li&gt;
&lt;/ol&gt;</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/698/gate-xe-2025-question-92</guid>
<pubDate>Sun, 04 May 2025 19:05:58 +0000</pubDate>
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<title>GATE XE 2025 | Question: 97</title>
<link>https://xe.gateoverflow.in/693/gate-xe-2025-question-97</link>
<description>&lt;p&gt;​​​​For an ideal gas turbine cycle, $T_{1}$ and $T_{3}$ are the compressor inlet temperature and turbine inlet temperature respectively. The ratio $\frac{T_{3}}{T_{1}}$ is denoted by $t$ and the ratio of specific heats is denoted by $\gamma$. For any given $t$, the optimum pressure ratio for the maximum specific work output is&lt;/p&gt;

&lt;ol start=&quot;1&quot; style=&quot;list-style-type:upper-alpha&quot;&gt;
	&lt;li&gt;$t^{\frac{2}{(\gamma-1)}}$&lt;/li&gt;
	&lt;li&gt;$t^{\frac{\gamma}{2(\gamma-1)}}$&lt;/li&gt;
	&lt;li&gt;$t^{\frac{\gamma}{(\gamma-1)}}$&lt;/li&gt;
	&lt;li&gt;$t^{\frac{\gamma-1}{\gamma}}$&lt;/li&gt;
&lt;/ol&gt;</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/693/gate-xe-2025-question-97</guid>
<pubDate>Sun, 04 May 2025 19:05:50 +0000</pubDate>
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<title>GATE XE 2025 | Question: 101</title>
<link>https://xe.gateoverflow.in/689/gate-xe-2025-question-101</link>
<description>Air in an ideal Diesel cycle is compressed from $3 \: \mathrm{litre}$ to $0.15 \: \mathrm{litre}$. It then expands during a constant pressure heat addition process to $0.3 \: \mathrm{litre}$. If the ratio of specific heats, $\gamma=1.4$, the thermal efficiency (in $\%$ ) of the cycle is $\_\_\_\_\_\_\_$ (rounded to one decimal place).</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/689/gate-xe-2025-question-101</guid>
<pubDate>Sun, 04 May 2025 19:05:40 +0000</pubDate>
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<title>GATE XE 2024 | Question: 93</title>
<link>https://xe.gateoverflow.in/323/gate-xe-2024-question-93</link>
<description>Consider the following data from a Brayton cycle.&lt;br /&gt;
&lt;br /&gt;
Enthalpy at inlet to turbine; $1400 \mathrm{~kJ} / \mathrm{kg}$&lt;br /&gt;
&lt;br /&gt;
Enthalpy at exit of turbine: $880 \mathrm{~kJ} / \mathrm{kg}$&lt;br /&gt;
&lt;br /&gt;
Enthalpy at exit of compressor: $600 \mathrm{~kJ} / \mathrm{kg}$&lt;br /&gt;
&lt;br /&gt;
On adding a regenerator of effectiveness equal to $0.8$, the absolute value of percentage change in heat addition is __________ $\text{(rounded off to the nearest integer)}$.</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/323/gate-xe-2024-question-93</guid>
<pubDate>Sun, 21 Jul 2024 16:41:27 +0000</pubDate>
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<title>GATE XE 2023 | Question: 88</title>
<link>https://xe.gateoverflow.in/153/gate-xe-2023-question-88</link>
<description>&lt;img alt=&quot;GATE XE 2023 | Question-88&quot; src=&quot;https://xe.gateoverflow.in/?qa=blob&amp;amp;qa_blobid=5785377139862162521&quot;&gt;&lt;p&gt;\begin{tabular}{|l|l|} &lt;br&gt;
Q.98 &amp;amp; \begin{tabular}{l} &lt;br&gt;
An ideal Diesel cycle has a compression ratio of 20 and cut-off ratio of 1.5. At the \\&lt;br&gt;
beginning of the compression stroke, air is at $100 \mathrm{kPa}, 300 \mathrm{~K}$. Use the \\&lt;br&gt;
cold-air-standard assumptions with property value $c_{p}=1.005 \mathrm{~kJ} / \mathrm{kg}-\mathrm{K}$. Assume \\&lt;br&gt;
$c_{p} / c_{v}=1.4$. For this cycle, the net work output per unit mass is&lt;br&gt;
\end{tabular} \\&lt;br&gt;
\hline &lt;/p&gt;&lt;ol style=&quot;list-style-type:upper-alpha&quot;&gt;&lt;li&gt;  &amp;amp; $335 \mathrm{~kJ} / \mathrm{kg}$ \\&lt;br&gt;
\hline &lt;/li&gt;&lt;li&gt;  &amp;amp; $395 \mathrm{~kJ} / \mathrm{kg}$ \\&lt;br&gt;
\hline &lt;/li&gt; &lt;li&gt; &amp;amp; $500 \mathrm{~kJ} / \mathrm{kg}$ \\&lt;br&gt;
\hline &lt;/li&gt;  &lt;li&gt; &amp;amp; $165 \mathrm{~kJ} / \mathrm{kg}$&lt;br&gt;
\end{tabular}  &lt;/li&gt;&lt;/ol&gt;</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/153/gate-xe-2023-question-88</guid>
<pubDate>Wed, 14 Feb 2024 18:08:57 +0000</pubDate>
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<title>GATE XE 2023 | Question: 95</title>
<link>https://xe.gateoverflow.in/146/gate-xe-2023-question-95</link>
<description>&lt;img alt=&quot;GATE XE 2023 | Question-95&quot; src=&quot;https://xe.gateoverflow.in/?qa=blob&amp;amp;qa_blobid=17184234597034676197&quot;&gt;&lt;p&gt;Q. 105 A refrigerator operates on an ideal vapor compression cycle between the pressure limits of $140 \mathrm{kPa}$ and $800 \mathrm{kPa}$. The working fluid is the refrigerant R-134a. The refrigerant enters the compressor as saturated vapor at $140 \mathrm{kPa}$ and exits at 800 $\mathrm{kPa}$ and $60{ }^{\circ} \mathrm{C}$. It leaves the condenser as a saturated liquid at $800 \mathrm{kPa}$. The coefficient of performance (COP) of the refrigerator is (rounded off to two decimal places).&lt;br&gt;
Use the following property data for R-134a:&lt;br&gt;
At $140 \mathrm{kPa}$ :&lt;br&gt;
$h_{f}=27.06 \mathrm{~kJ} / \mathrm{kg}$, $h_{g}=239.19 \mathrm{~kJ} / \mathrm{kg}$&lt;br&gt;
At $800 \mathrm{kPa}$ :&lt;br&gt;
$h_{f}=95.48 \mathrm{~kJ} / \mathrm{kg}$,&lt;br&gt;
$h_{g}=267.34 \mathrm{~kJ} / \mathrm{kg}$&lt;br&gt;
At $800 \mathrm{kPa}$ and $60^{\circ} \mathrm{C}: \quad h=296.82 \mathrm{~kJ} / \mathrm{kg}$&lt;/p&gt;</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/146/gate-xe-2023-question-95</guid>
<pubDate>Wed, 14 Feb 2024 18:08:51 +0000</pubDate>
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<title>GATE XE 2023 | Question: 96</title>
<link>https://xe.gateoverflow.in/145/gate-xe-2023-question-96</link>
<description>&lt;img alt=&quot;GATE XE 2023 | Question-96&quot; src=&quot;https://xe.gateoverflow.in/?qa=blob&amp;amp;qa_blobid=2855807719391378998&quot;&gt;&lt;p&gt;Q. 106&lt;br&gt;
A steam power plant operates on a simple ideal Rankine cycle. The condenser pressure is $10 \mathrm{kPa}$ and the boiler pressure is $5 \mathrm{MPa}$. The steam enters the turbine at $600^{\circ} \mathrm{C}$. Mass flow rate of the steam is $50 \mathrm{~kg} / \mathrm{s}$. Neglecting the pump work, the net power output of the plant is MW (rounded off to one decimal place).&lt;br&gt;
&lt;br&gt;
Use the following property data for water:&lt;br&gt;
At $10 \mathrm{kPa}$ :&lt;br&gt;
\[&lt;br&gt;
\begin{array}{l}&lt;br&gt;
h_{f}=191.81 \mathrm{~kJ} / \mathrm{kg}, \quad h_{f g}=2392.82 \mathrm{~kJ} / \mathrm{kg}, \quad h_{g}=2584.63 \mathrm{~kJ} / \mathrm{kg} \\&lt;br&gt;
s_{f}=0.6492 \mathrm{~kJ} / \mathrm{kg}-\mathrm{K}, \quad s_{f g}=7.5010 \mathrm{~kJ} / \mathrm{kg}-\mathrm{K}, \quad s_{g}=8.1502 \mathrm{~kJ} / \mathrm{kg}-\mathrm{K}&lt;br&gt;
\end{array}&lt;br&gt;
\]&lt;br&gt;
&lt;br&gt;
At $5 \mathrm{MPa}$ and $600{ }^{\circ} \mathrm{C}$ :&lt;br&gt;
\[&lt;br&gt;
h=3666.47 \mathrm{~kJ} / \mathrm{kg}, \quad s=7.2588 \mathrm{~kJ} / \mathrm{kg}-\mathrm{K}&lt;br&gt;
\]&lt;/p&gt;</description>
<category>Thermodynamic Cycles</category>
<guid isPermaLink="true">https://xe.gateoverflow.in/145/gate-xe-2023-question-96</guid>
<pubDate>Wed, 14 Feb 2024 18:08:49 +0000</pubDate>
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