Consider that specific heat $\left(0\right.$ to $\left.50^{\circ} \mathrm{C}\right)$ of water, water vapour and air remains constant: $4.48,1.88$ and $1.0 \mathrm{~kJ} /\left(\mathrm{kg}{ }^{\circ} \mathrm{C}\right)$, respectively. Assuming, the heat energy required to convert $1 \: \mathrm{kg}$ of water to water vapour at $0^{\circ} \mathrm{C}$ is $2000 \: \mathrm{kJ}$, the enthalpy (in $\mathrm{kJ} / \mathrm{kg}$ dry air) of atmospheric air containing $0.05 \: \mathrm{kg}$ water vapour per $\mathrm{kg}$ dry air at $50^{\circ} \mathrm{C}$ is $\_\_\_\_\_\_\_\_$. (rounded off to $1$ decimal place).
