Register

GATE XE 2025 | Question: 92

• edited by
0 0 votes

​​​​​If $\gamma$ refers to the ratio of specific heats, the air-standard efficiency of an Otto cycle is

  1. $1-\frac{1}{(\text { Compression ratio })^{\gamma}}$
  2. $1-\frac{1}{(\text { Pressure ratio) } ^{\frac{\gamma-1}{\gamma}}.}$
  3. $1-\frac{1}{(\text { Compression ratio })^{(\gamma-1)}}$
  4. $1-\frac{1}{(\text { Pressure ratio })^{(\gamma-1)}}$

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Answer:
Voting & Accepting an answer helps improve the community