Let $y(x)$ be the solution of the initial value problem,
$$\begin{array}{c}
x^{2} y^{\prime \prime}+x y^{\prime}-y=0, \quad x>0, \\
y(1)=0, \quad y^{\prime}(1)=2 .
\end{array}$$
Then the value of $y^{\prime}\left(\frac{1}{2}\right)$ is equal to (Answer in integer) $\_\_\_\_\_\_\_$
