It is given that: $\left(\dfrac{\partial h}{\partial T}\right)_{P}=c_{p}$ and $\left(\dfrac{\partial h}{\partial P}\right)_{T}=(v-\beta T v)$. Here $h$ is the mass specific enthalpy, $v$ is the mass specific volume, $\beta=\dfrac{1}{v}\left(\dfrac{\partial v}{\partial T}\right)_{P}$ is the volume expansivity, and $c_{p}$ is the mass specific heat capacity at constant pressure. $T$ and $P$ represent the temperature and the pressure, respectively. The inversion temperature is the temperature at which the Joule-Thomson coefficient, $\mu_{\mathrm{JT}}=\left(\frac{\partial T}{\partial P}\right)_{h}$, goes to zero. Consider a fluid with properties: $v=1.03 \mathrm{~m}^{3} / \mathrm{kg}, c_{P}=1 \mathrm{~kJ} / \mathrm{kg}-\mathrm{K}$, and $\beta=4.39 \times 10^{-3} 1 / \mathrm{K}$;
The inversion temperature (in $\mathrm{K}$) for the fluid is $\_\_\_\_$ (rounded off to two decimal places).
