A tubular centrifuge separates $5$ micron particles of density $1500 \mathrm{~kg/m}^{3}$ from a slurry. The slurry is fed at a volumetric flow rate of $0.5 \mathrm{~m}^{3}/s$. The equivalent clarification area of the centrifuge is ________ $\mathrm{~m}^{2}$. (Answer in integer)
Assume $\text{g}=10 \mathrm{~m/s}^{2}$ and for water, density = $1000 \mathrm{~kg/m}^{3}$, coefficient of viscosity $(μ)=10^{-3} \mathrm{~Pa-s}$
